Three blocks of masses $m$, $2m$, and $3m$ are pushed with a force $F$ across a frictionless table as shown in the figure. Let $N_{1}$ be the contact force between the left two blocks ($m$ and $2m$) and $N_{2}$ be the contact force between the right two blocks ($2m$ and $3m$). Then:

  • A
    $F > N_{1} > N_{2}$
  • B
    $F > N_{2} > N_{1}$
  • C
    $F > N_{1} = N_{2}$
  • D
    $F = N_{1} = N_{2}$

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