Three capacitances of capacity $10\,\mu F$,$5\,\mu F$,and $5\,\mu F$ are connected in parallel. The total capacity will be ........ $\mu F$.

Three capacitors each of capacitance $9 \;pF$ are connected in series.
$(a)$ What is the total capacitance of the combination?
$(b)$ What is the potential difference across each capacitor if the combination is connected to a $120 \;V$ supply?

To obtain $3\,\mu F$ capacitance from three capacitors of $2\,\mu F$ each,they will be arranged as:

$A$ series combination of three capacitors of capacities $1\,\mu F$,$2\,\mu F$,and $8\,\mu F$ is connected to a battery of $e.m.f.$ $13\,V$. The potential difference across the plates of the $2\,\mu F$ capacitor will be.....$V$

The minimum number of capacitors of $2\,\mu F$ capacitance each required to obtain a resultant capacitance of $5\,\mu F$ is

The equivalent capacitance between $ A $ and $ B $ is,