Three capacitors each of 6,mu F are available | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To obtain the minimum capacitance,the capacitors must be connected in series.For $n$ identical capacitors of capacitance $C$ in series,the equival

Vedclass · Accepted Answer

$2\,\mu F, 18\,\mu F$

Vedclass · Answer

(D) To obtain the minimum capacitance,the capacitors must be connected in series.For $n$ identical capacitors of capacitance $C$ in series,the equivalent capacitance $C_{s}$ is given by $C_{s} = \frac{C}{n}$.Here,$C = 6\,\mu F$ and $n = 3$,so $C_{s} = \frac{6\,\mu F}{3} = 2\,\mu F$.To obtain the maximum capacitance,the capacitors must be connected in parallel.For $n$ identical capacitors of capacitance $C$ in parallel,the equivalent capacitance $C_{p}$ is given by $C_{p} = n 	imes C$.Here,$C_{p} = 3 	imes 6\,\mu F = 18\,\mu F$.Therefore,the minimum and maximum capacitances are $2\,\mu F$ and $18\,\mu F$ respectively.

Three capacitors each of $6\,\mu F$ are available. The minimum and maximum capacitances which may be obtained are

Similar Questions

Three long concentric conducting cylindrical shells have radii $R$,$2R$,and $2\sqrt{2}R$. The inner and outer shells are connected to each other. The capacitance across the middle and inner shells per unit length is:

The equivalent capacitance between points $A$ and $B$ in the figure shown below is .......... $\mu F$.

If the equivalent capacitance between points $A$ and $B$ of the combination of capacitors shown in the figure is $6C$, then the capacitor $C^1$ is: (in $C$)

In the circuit,two capacitors $C_1$ and $C_2$ are connected as shown in the figure. The potential at point $A$ is $V_1$ and at point $B$ is $V_2$. What is the potential at point $D$?

In the given network, the value of $C$, so that an equivalent capacitance between points $A$ and $B$ is $3 \mu F$, is

Vedclass Test Series

Exam Paper Generator

Online Exam Module