Three capacitors each of capacitance $1\,\mu F$ are connected in parallel. To this combination,a fourth capacitor of capacitance $1\,\mu F$ is connected in series. The resultant capacitance of the system is.......$\mu F$

The equivalent capacitance between the points $A$ and $B$ of the network shown in the figure is (in $\text{ F}$)

Four identical capacitors are connected in series with a battery of $emf$ $10 \, V$. The point $X$ is earthed. Find the potential of point $A$. (in $, V$)

As shown in the circuit below,the effective capacitance is . . . . . . $\mu F$.

Two capacitors of capacitance $2\ \mu F$ and $3\ \mu F$ are joined in series. The outer plate of the first capacitor is at $1000\ V$ and the outer plate of the second capacitor is earthed (grounded). The potential on the inner plates of each capacitor will be: (in $V$)

When three capacitors of equal capacities are connected in parallel and one of the same capacity is connected in series with the combination,the resultant capacity is $4.5 \mu F$. The capacity of each capacitor is: (in $\mu F$)