Three capacitors of capacitance 1 mu F,2 mu F | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a series combination,the equivalent capacitance $C_{eq}$ is given by $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}$.Substit

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(D) In a series combination,the equivalent capacitance $C_{eq}$ is given by $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}$.Substituting the values: $\frac{1}{C_{eq}} = \frac{1}{1} + \frac{1}{2} + \frac{1}{3} = \frac{6+3+2}{6} = \frac{11}{6}$.Thus,$C_{eq} = \frac{6}{11}\ \mu F$.The total charge $Q$ supplied by the battery is $Q = C_{eq} 	imes V = \frac{6}{11}\ \mu F 	imes 11\ V = 6\ \mu C$.In a series circuit,the charge on each capacitor is the same. Therefore,the charge on the $1\ \mu F$ capacitor is $6\ \mu C$.The potential difference $V_1$ across the $1\ \mu F$ capacitor is $V_1 = \frac{Q}{C_1} = \frac{6\ \mu C}{1\ \mu F} = 6\ V$.

Three capacitors of capacitance $1\ \mu F$,$2\ \mu F$,and $3\ \mu F$ are connected in series,and a potential difference of $11\ V$ is applied across the combination. The potential difference across the plates of the $1\ \mu F$ capacitor is......$V$.

Similar Questions

Four identical capacitors are connected in series with a $10\,V$ battery as shown. The point $N$ is earthed. The potentials of points $A$ and $B$ are

Two capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. $A$ potential difference of $500\;V$ is applied to the outer plates of the two-capacitor system. The charge on each capacitor is numerically:

$A$ parallel combination of three capacitors of capacities $2C$,$C$,and $C/2$ is connected across a $10 \ V$ battery. All the capacitors are fully charged to charges $Q_1$,$Q_2$,and $Q_3$ respectively. The ratio $Q_1: Q_2: Q_3$ is

If the equivalent capacitance between points $A$ and $B$ of the combination of capacitors shown in the figure is $6C$, then the capacitor $C^1$ is: (in $C$)

In the circuit diagram shown in the adjoining figure,the resultant capacitance between $P$ and $Q$ is ........ $\mu F$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module