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(D) When three coins are tossed,the total number of possible outcomes is $2^3 = 8$. The sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\

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$\frac{7}{8}$

Vedclass · Answer

(D) When three coins are tossed,the total number of possible outcomes is $2^3 = 8$. The sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$. Let $E$ be the event of getting at least one head. The complement event $E'$ is the event of getting no heads,which means all tails. $E' = \{TTT\}$,so $n(E') = 1$. The probability of getting no heads is $P(E') = \frac{n(E')}{n(S)} = \frac{1}{8}$. The probability of getting at least one head is $P(E) = 1 - P(E') = 1 - \frac{1}{8} = \frac{7}{8}$.

Three coins are tossed together,then the probability of getting at least one head is

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