Three conductors draw currents of 1 ,A, 2 ,A | vedclass

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(A) Let the resistances of the three conductors be $R_1, R_2$ and $R_3$. When connected individually across a battery of voltage $V$, the currents are

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$\frac{6}{11} \,A$

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(A) Let the resistances of the three conductors be $R_1, R_2$ and $R_3$. When connected individually across a battery of voltage $V$, the currents are $I_1 = 1 \,A, I_2 = 2 \,A$ and $I_3 = 3 \,A$.Using Ohm's law, $V = I R$, we have:$R_1 = \frac{V}{1} = V$$R_2 = \frac{V}{2}$$R_3 = \frac{V}{3}$When connected in series, the equivalent resistance $R_{eq}$ is:$R_{eq} = R_1 + R_2 + R_3 = V + \frac{V}{2} + \frac{V}{3} = V \left( 1 + \frac{1}{2} + \frac{1}{3} \right) = V \left( \frac{6 + 3 + 2}{6} \right) = \frac{11V}{6}$The current $I$ drawn from the same battery in series is:$I = \frac{V}{R_{eq}} = \frac{V}{11V/6} = \frac{6}{11} \,A$.

Three conductors draw currents of $1 \,A, 2 \,A$ and $3 \,A$ respectively, when connected in turn across a battery. If they are connected in series and the combination is connected across the same battery, the current drawn will be

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