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(D) The total number of outcomes when three dice are thrown is $N = 6^3 = 216$.We need to find the number of outcomes where the sum of the numbers on

Vedclass · Accepted Answer

$\frac{1}{36}$

Vedclass · Answer

(D) The total number of outcomes when three dice are thrown is $N = 6^3 = 216$.We need to find the number of outcomes where the sum of the numbers on the three dice is $16$.The possible combinations of numbers that sum to $16$ are:$1) (6, 6, 4)$ which can be arranged in $\frac{3!}{2!} = 3$ ways.$2) (6, 5, 5)$ which can be arranged in $\frac{3!}{2!} = 3$ ways.Total favorable outcomes $= 3 + 3 = 6$.Therefore,the required probability $= \frac{	ext{Favorable outcomes}}{	ext{Total outcomes}} = \frac{6}{216} = \frac{1}{36}$.

Three dice are thrown. Find the chance of getting a sum of $16$.

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