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(C) The total number of outcomes when three dice are thrown simultaneously is $6 	imes 6 	imes 6 = 216$.$A$ total of $17$ can be obtained in the fol

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$\frac{1}{54}$

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(C) The total number of outcomes when three dice are thrown simultaneously is $6 	imes 6 	imes 6 = 216$.$A$ total of $17$ can be obtained in the following ways: $(5, 6, 6), (6, 5, 6), (6, 6, 5)$. There are $3$ such outcomes.$A$ total of $18$ can be obtained in the following way: $(6, 6, 6)$. There is $1$ such outcome.The total number of favorable outcomes is $3 + 1 = 4$.Therefore,the required probability is $\frac{4}{216} = \frac{1}{54}$.

Three dice are thrown simultaneously. What is the probability of obtaining a total of $17$ or $18$?

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