Three energy levels of a hydrogen atom and the corresponding wavelengths of the emitted radiation due to different electron transitions are as shown. Then,

  • A
    $\lambda_3=\frac{\lambda_1 \lambda_2}{\lambda_1+\lambda_2}$
  • B
    $\lambda_1=\frac{\lambda_2 \lambda_3}{\lambda_2+\lambda_3}$
  • C
    $\lambda_2=\lambda_1+\lambda_3$
  • D
    $\lambda_2=\frac{\lambda_1 \lambda_3}{\lambda_1+\lambda_3}$

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In a hydrogen atom,which of the following transitions will have the minimum wavelength?

An electron makes a transition from an excited state to the ground state of a hydrogen-like atom. Out of the following statements,which one is correct?

For a certain hypothetical one-electron atom,the wavelength (in $\mathring{A}$) for the spectral lines for transition from $n = p$ to $n = 1$ is given by $\lambda = \frac{1500p^2}{p^2 - 1}$ (where $p > 1$). The ionization potential of this element must be ......$V$ (Take $hc = 12420 \text{ eV-} \mathring{A}$).

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The ground state energy of a hydrogen atom is $-13.6 \text{ eV}$. When its electron is in the first excited state,its excitation energy is:

$A$ sample of hydrogen atoms is in an excited state (all the atoms). The photons emitted from this sample are made to pass through a filter through which light having a wavelength greater than $800 \ nm$ can only pass. Only one type of photon is found to pass through the filter. The sample's initial excited state is: [Take $hc = 1240 \ eV \cdot nm$,ground state energy of hydrogen atom = $-13.6 \ eV$.]

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