Three identical cells,each of emf 10 V and i | vedclass

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(A) For cells connected in parallel,the equivalent emf $E_{	ext{eq}}$ is given by the formula:$E_{	ext{eq}} = \frac{\sum \frac{E_i}{r_i}}{\sum \frac

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$10$

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(A) For cells connected in parallel,the equivalent emf $E_{	ext{eq}}$ is given by the formula:$E_{	ext{eq}} = \frac{\sum \frac{E_i}{r_i}}{\sum \frac{1}{r_i}}$Given that all three cells are identical with $E = 10 \ V$ and $r = 3 \ \Omega$,we have:$E_{	ext{eq}} = \frac{\frac{10}{3} + \frac{10}{3} + \frac{10}{3}}{\frac{1}{3} + \frac{1}{3} + \frac{1}{3}}$$E_{	ext{eq}} = \frac{10}{1} = 10 \ V$Alternatively,for identical cells in parallel,the equivalent emf is equal to the emf of a single cell. Thus,the net emf is $10 \ V$.

Three identical cells,each of emf $10 \ V$ and internal resistance $3 \ \Omega$,are connected in parallel across terminals $A$ and $B$. The net emf across $A$ and $B$ is .......... $V$.

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