Three identical dice are rolled. The probabil | vedclass

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(B) When three dice are rolled,the total number of possible outcomes is $6 	imes 6 	imes 6 = 216$.The favorable outcomes where the same number appea

Vedclass · Accepted Answer

$\frac{1}{36}$

Vedclass · Answer

(B) When three dice are rolled,the total number of possible outcomes is $6 	imes 6 	imes 6 = 216$.The favorable outcomes where the same number appears on each die are: $(1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6)$.There are $6$ such favorable outcomes.Therefore,the required probability is $\frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{6}{216} = \frac{1}{36}$.

Three identical dice are rolled. The probability that the same number will appear on each of them is:

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