Three identical spheres,each of mass $M$,are placed at the corners of a right-angled triangle with mutually perpendicular sides equal to $2 \; m$ (see figure). Taking the point of intersection of the two mutually perpendicular sides as the origin,find the position vector of the center of mass.
- A$\frac{4}{3}(\hat{i}+\hat{j})$
- B$2(\hat{i}+\hat{j})$
- C$(\hat{i}+\hat{j})$
- D$\frac{2}{3}(\hat{i}+\hat{j})$
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