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(D) The time taken by each man to complete one revolution is calculated as $	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}}$.For the first man: $T_

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$22$

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(D) The time taken by each man to complete one revolution is calculated as $	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}}$.For the first man: $T_1 = \frac{11}{4} 	ext{ hours}$.For the second man: $T_2 = \frac{11}{5.5} = \frac{11}{11/2} = 2 	ext{ hours}$.For the third man: $T_3 = \frac{11}{8} 	ext{ hours}$.The time at which they will meet at the starting point is the Least Common Multiple $(LCM)$ of the times taken to complete one revolution: $	ext{LCM}(\frac{11}{4}, 2, \frac{11}{8})$.To find the $LCM$ of fractions,use the formula: $	ext{LCM}(\frac{a}{b}, \frac{c}{d}, \frac{e}{f}) = \frac{	ext{LCM}(a, c, e)}{	ext{HCF}(b, d, f)}$.Here,the fractions are $\frac{11}{4}, \frac{2}{1}, \frac{11}{8}$.$	ext{LCM}(11, 2, 11) = 22$.$	ext{HCF}(4, 1, 8) = 1$.Therefore,the required time is $\frac{22}{1} = 22 	ext{ hours}$.

Three men start together to travel the same way around a circular track of $11 \text{ km}$ in circumference. Their speeds are $4 \text{ km/h}$,$5.5 \text{ km/h}$,and $8 \text{ km/h}$ respectively. When will they meet at the starting point? (in hours)

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