Three numbers are in the ratio $3:4:5$. The sum of the largest and the smallest equals the sum of the third and $52$. The smallest number is

$[(3^{2})^{6}]^{5} = 9^{?}$

The price of commodity $X$ increases by $40 \text{ paise}$ every year,while the price of commodity $Y$ increases by $15 \text{ paise}$ every year. If in $2001$,the price of commodity $X$ was $Rs. 4.20$ and that of $Y$ was $Rs. 6.30$,in which year will commodity $X$ cost $40 \text{ paise}$ more than commodity $Y$?

The value of $(1001)^3$ is

$499.99 + 1999 \div 39.99 \times 50.01 = ?$

$69.69 - 51.54 + 73.64 = ? + 32.42$