Three plates A, B, C each of area 50 , cm^2 h | vedclass

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(B) From the figure, plates $A$ and $C$ are connected together, and plate $B$ is connected to the other terminal of the battery. This forms two capaci

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$2.1 	imes 10^{-9} \, J$

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(B) From the figure, plates $A$ and $C$ are connected together, and plate $B$ is connected to the other terminal of the battery. This forms two capacitors in parallel, one between $A$ and $B$, and another between $B$ and $C$.Given: Area $A = 50 \, cm^2 = 50 	imes 10^{-4} \, m^2$, separation $d = 3 \, mm = 3 	imes 10^{-3} \, m$, and voltage $V = 12 \, V$.The capacitance of each capacitor is $C_0 = \frac{\varepsilon_0 A}{d}$.Since they are in parallel, the total capacitance is $C_{eq} = C_0 + C_0 = \frac{2 \varepsilon_0 A}{d}$.Substituting the values:$C_{eq} = \frac{2 	imes 8.854 	imes 10^{-12} 	imes 50 	imes 10^{-4}}{3 	imes 10^{-3}} \approx 2.95 	imes 10^{-11} \, F$.The energy stored $U = \frac{1}{2} C_{eq} V^2 = \frac{1}{2} 	imes (2.95 	imes 10^{-11}) 	imes (12)^2$.$U = 0.5 	imes 2.95 	imes 10^{-11} 	imes 144 = 2.124 	imes 10^{-9} \, J \approx 2.1 	imes 10^{-9} \, J$.

Three plates $A, B, C$ each of area $50 \, cm^2$ have a separation of $3 \, mm$ between $A$ and $B$ and $3 \, mm$ between $B$ and $C$. The energy stored when the plates are fully charged is (as shown in the figure):

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