Three prisms 1, 2 and 3 have the prism angle | vedclass

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Question

(A) For a thin prism,the angle of deviation $\delta$ is given by the formula $\delta = (\mu - 1)A$,where $\mu$ is the refractive index of the material

Vedclass · Accepted Answer

$\delta_3 > \delta_2 > \delta_1$

Vedclass · Answer

(A) For a thin prism,the angle of deviation $\delta$ is given by the formula $\delta = (\mu - 1)A$,where $\mu$ is the refractive index of the material of the prism and $A$ is the prism angle.Given that the prism angle $A = 60^o$ is the same for all three prisms,the angle of deviation $\delta$ depends directly on the refractive index $\mu$ such that $\delta \propto (\mu - 1)$.For the given prisms:$\mu_1 = 1.4 \implies \delta_1 = (1.4 - 1) 	imes 60^o = 0.4 	imes 60^o = 24^o$$\mu_2 = 1.5 \implies \delta_2 = (1.5 - 1) 	imes 60^o = 0.5 	imes 60^o = 30^o$$\mu_3 = 1.6 \implies \delta_3 = (1.6 - 1) 	imes 60^o = 0.6 	imes 60^o = 36^o$Comparing the values,we get $\delta_3 > \delta_2 > \delta_1$.

Three prisms $1, 2$ and $3$ have the prism angle $A = 60^o$,but their refractive indices are respectively $1.4, 1.5$ and $1.6$. If $\delta_1, \delta_2, \delta_3$ be their respective angles of deviation,then:

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