Three resistors 1 Omega, 2 Omega and 3 Omega | vedclass

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(B) The resistors $1 \Omega$ and $2 \Omega$ are connected in series along the path $ABC$. The equivalent resistance of this branch is $R_{ABC} = 1 \Om

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(B) The resistors $1 \Omega$ and $2 \Omega$ are connected in series along the path $ABC$. The equivalent resistance of this branch is $R_{ABC} = 1 \Omega + 2 \Omega = 3 \Omega$.This branch is connected in parallel with the $3 \Omega$ resistor connected directly across the battery terminals $A$ and $C$.The potential difference across the $3 \Omega$ resistor is equal to the battery voltage,$V = 3 	ext{ V}$.Using Ohm's law,the current $I$ through the $3 \Omega$ resistor is given by:$I = \frac{V}{R} = \frac{3 	ext{ V}}{3 \Omega} = 1 	ext{ A}$.

Three resistors $1 \Omega, 2 \Omega$ and $3 \Omega$ are connected to form a triangle. Across the $3 \Omega$ resistor,a $3 \text{ V}$ battery is connected. The current through the $3 \Omega$ resistor is: (in $\text{ A}$)

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