Three solid spheres each of mass M and radius | vedclass

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(A) The moment of inertia of the upper sphere about the axis $YY'$ passing through its center is $I_1 = \frac{2}{5} MR^2$.For each of the two lower sp

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$\frac{16}{5} MR^2$

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(A) The moment of inertia of the upper sphere about the axis $YY'$ passing through its center is $I_1 = \frac{2}{5} MR^2$.For each of the two lower spheres,the axis $YY'$ is at a distance $R$ from their centers. Using the parallel axis theorem,the moment of inertia for each lower sphere is $I_2 = I_{cm} + MR^2 = \frac{2}{5} MR^2 + MR^2 = \frac{7}{5} MR^2$.Therefore,the total moment of inertia of the system is $I = I_1 + 2 	imes I_2 = \frac{2}{5} MR^2 + 2 	imes \frac{7}{5} MR^2 = \frac{2}{5} MR^2 + \frac{14}{5} MR^2 = \frac{16}{5} MR^2$.

Three solid spheres each of mass $M$ and radius $R$ are arranged as shown in the figure. The moment of inertia of the system about $YY'$ will be

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