(C) The total mass of the system is $M = m_1 + m_2 + m_3$.Since the system is pulled by a force $T$ on a frictionless surface,the acceleration $a$ of

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$\frac{m_1 + m_2}{m_1 + m_2 + m_3} T$

(C) The total mass of the system is $M = m_1 + m_2 + m_3$.Since the system is pulled by a force $T$ on a frictionless surface,the acceleration $a$ of the system is given by $a = \frac{T}{m_1 + m_2 + m_3}$.To find the tension $T'$ in the string between $m_2$ and $m_3$,we consider the system consisting of masses $m_1$ and $m_2$ being pulled by this tension $T'$.Applying Newton's second law to this subsystem: $T' = (m_1 + m_2) a$.Substituting the value of $a$: $T' = (m_1 + m_2) \times \frac{T}{m_1 + m_2 + m_3}$.Thus,the tension is $\frac{m_1 + m_2}{m_1 + m_2 + m_3} T$.

Class 11 Physics Laws of Motion Motion of Body (or Connected Bodies in horizontal or vertical) (by String or Contact)

Easy

Three solids of masses $m_1, m_2$ and $m_3$ are connected with weightless strings in succession and are placed on a frictionless table. If the mass $m_3$ is dragged with a force $T$,the tension in the string between $m_2$ and $m_3$ is

A
$\frac{m_2}{m_1 + m_2 + m_3} T$
B
$\frac{m_3}{m_1 + m_2 + m_3} T$
C
$\frac{m_1 + m_2}{m_1 + m_2 + m_3} T$
D
$\frac{m_2 + m_3}{m_1 + m_2 + m_3} T$

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Motion of Body (or Connected Bodies in horizontal or vertical) (by String or Contact)

Two blocks,each of mass $M$,are initially at rest on frictionless surfaces as shown in the figure. If the pulleys are light and frictionless,and the block of mass $M$ on the incline is allowed to move down,then the tension in the string will be$-$

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$A$ balloon of mass $M$ descends with an acceleration $a (< g)$. What mass needs to be removed from the balloon so that it starts ascending with acceleration $a$?

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$A$ steel block of $10\, \text{kg}$ rests on a horizontal floor. When three iron cylinders,each of mass $20\, \text{kg}$,are placed on it as shown,the entire system (block + cylinders) moves downward with an acceleration of $0.2\, \text{m/s}^2$. The normal reaction $R$ exerted by the floor is ..... $\text{N}$. [Take $g = 10\, \text{m/s}^2$]

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For the given figure,the tension in the string $T_1$ is .......... $N$.

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Two blocks are in contact on a frictionless table. One has mass $m$ and the other $2\,m$. $A$ force $F$ is applied on $2\,m$ as shown in the figure. Now,the same force $F$ is applied from the right on $m$. In the two cases respectively,what is the ratio of the contact force between the two blocks?

Medium

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Three solids of masses $m_1, m_2$ and $m_3$ are connected with weightless strings in succession and are placed on a frictionless table. If the mass $m_3$ is dragged with a force $T$,the tension in the string between $m_2$ and $m_3$ is

Similar Questions

Two blocks,each of mass $M$,are initially at rest on frictionless surfaces as shown in the figure. If the pulleys are light and frictionless,and the block of mass $M$ on the incline is allowed to move down,then the tension in the string will be$-$

$A$ balloon of mass $M$ descends with an acceleration $a (< g)$. What mass needs to be removed from the balloon so that it starts ascending with acceleration $a$?

For the given figure,the tension in the string $T_1$ is .......... $N$.

Two blocks are in contact on a frictionless table. One has mass $m$ and the other $2\,m$. $A$ force $F$ is applied on $2\,m$ as shown in the figure. Now,the same force $F$ is applied from the right on $m$. In the two cases respectively,what is the ratio of the contact force between the two blocks?

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