(B) Let the total capacity of the cistern be the least common multiple of $3, 4,$ and $5$,which is $60$ units.Efficiency of the first tap $= 60 / 3 =

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(B) Let the total capacity of the cistern be the least common multiple of $3, 4,$ and $5$,which is $60$ units.Efficiency of the first tap $= 60 / 3 = 20$ units/h.Efficiency of the second tap $= 60 / 4 = 15$ units/h.Efficiency of the third tap (emptying) $= - (60 / 5) = -12$ units/h.When all three taps are opened simultaneously,the net efficiency $= 20 + 15 - 12 = 23$ units/h.Time taken to fill the cistern $= \text{Total capacity} / \text{Net efficiency} = 60 / 23 \, h = 2 \frac{14}{23} \, h$.

Competitive Quantitative Aptitude Pipes and Cistern Pipes and Cistern

Easy

Three taps are fitted to a cistern. The empty cistern is filled by the first and second taps in $3$ and $4 \, h$,respectively. The full cistern is emptied by the third tap in $5 \, h$. If all three taps are opened simultaneously,the empty cistern will be filled up in?

A
$1 \frac{14}{23} \, h$
B
$2 \frac{14}{23} \, h$
C
$2 \, h \, 40 \, min$
D
$1 \, h \, 56 \, min$

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Pipes and Cistern

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Pipes and Cistern

Three pipes $A, B$ and $C$ can fill a cistern in $6$ $hrs$. After working together for $2$ $hrs$,$C$ is closed and $A$ and $B$ fill the remaining part of the cistern in $8$ $hrs$. Find the time (in $hrs$) in which the cistern can be filled by pipe $C$ alone.

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One tap can fill a cistern in $2$ $hours$ and another can empty the cistern in $3$ $hours.$ How long will they take to fill the cistern if both the taps are opened?

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$A$ pipe can fill a cistern in $4$ $min$ and another pipe can fill it in $5$ $min,$ but a third pipe can empty it in $2$ $min.$ The first two pipes are kept open for $2$ $min$ in the beginning and then the third pipe is also opened. Time (in $min$) taken to empty the cistern is?

Medium

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Two pipes can fill a cistern in $14$ $h$ and $16$ $h$,respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom,it took $92$ $min$ more to fill the cistern. When the cistern is full,in what time will the leak empty it?

Medium

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One fill pipe $A$ is $3$ times faster than second fill pipe $B$ and takes $32$ minutes less than the fill pipe $B$. When will the cistern be full if both the pipes are opened together?

Medium

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Three taps are fitted to a cistern. The empty cistern is filled by the first and second taps in $3$ and $4 \, h$,respectively. The full cistern is emptied by the third tap in $5 \, h$. If all three taps are opened simultaneously,the empty cistern will be filled up in?

Similar Questions

Three pipes $A, B$ and $C$ can fill a cistern in $6$ $hrs$. After working together for $2$ $hrs$,$C$ is closed and $A$ and $B$ fill the remaining part of the cistern in $8$ $hrs$. Find the time (in $hrs$) in which the cistern can be filled by pipe $C$ alone.

One tap can fill a cistern in $2$ $hours$ and another can empty the cistern in $3$ $hours.$ How long will they take to fill the cistern if both the taps are opened?

$A$ pipe can fill a cistern in $4$ $min$ and another pipe can fill it in $5$ $min,$ but a third pipe can empty it in $2$ $min.$ The first two pipes are kept open for $2$ $min$ in the beginning and then the third pipe is also opened. Time (in $min$) taken to empty the cistern is?

Two pipes can fill a cistern in $14$ $h$ and $16$ $h$,respectively. The pipes are opened simultaneously and it is found that due to leakage in the bottom,it took $92$ $min$ more to fill the cistern. When the cistern is full,in what time will the leak empty it?

One fill pipe $A$ is $3$ times faster than second fill pipe $B$ and takes $32$ minutes less than the fill pipe $B$. When will the cistern be full if both the pipes are opened together?

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