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(D) When three unbiased coins are tossed,the sample space $S$ is given by:$S = \{TTT, TTH, THT, HTT, THH, HTH, HHT, HHH\}$Total number of outcomes $N(

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$\frac{7}{8}$

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(D) When three unbiased coins are tossed,the sample space $S$ is given by:$S = \{TTT, TTH, THT, HTT, THH, HTH, HHT, HHH\}$Total number of outcomes $N(S) = 8$.Let $E$ be the event of getting at most two heads.This means we can have $0, 1,$ or $2$ heads.The outcomes corresponding to $E$ are:$E = \{TTT, TTH, THT, HTT, THH, HTH, HHT\}$Number of favorable outcomes $N(E) = 7$.The probability $P(E)$ is given by:$P(E) = \frac{N(E)}{N(S)} = \frac{7}{8}$.

Three unbiased coins are tossed once. What is the probability of getting at most two heads?

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