Threshold frequency for a metal is $15 \times 10^{14} \, Hz$. The light of wavelength $6000 \, \text{Å}$ falls on the metal surface. Then photoelectrons [velocity of light in air, $c = 3 \times 10^8 \, m/s$]:

  • A
    come out with zero velocity.
  • B
    come out with velocity $3 \times 10^6 \, m/s$.
  • C
    will not be emitted.
  • D
    are emitted with velocity $c$.

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