To convert 1-butyne to 1-D-butanal,one would | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The conversion of $1$-butyne $(CH_3CH_2C \equiv CH)$ to $1-D$-butanal $(CH_3CH_2CH_2CDO)$ requires the introduction of a deuterium atom at the $C-

Vedclass · Accepted Answer

$III$

Vedclass · Answer

(C) The conversion of $1$-butyne $(CH_3CH_2C \equiv CH)$ to $1-D$-butanal $(CH_3CH_2CH_2CDO)$ requires the introduction of a deuterium atom at the $C-1$ position and the conversion of the alkyne to an aldehyde. Step $I$ (Sodium amide,then $D_2O$) would produce $1-D$-butyne $(CH_3CH_2C \equiv CD)$. Step $II$ (Hydroboration-oxidation using disiamylborane followed by $H_2O_2/NaOH$) converts $1$-butyne to butanal $(CH_3CH_2CH_2CHO)$. To obtain $1-D$-butanal,one would need to perform hydroboration-oxidation on $1-D$-butyne using $D_2O_2/NaOD$ instead of $H_2O_2/NaOH$. Since the provided reagents in $I$ and $II$ do not lead to the desired product $1-D$-butanal,option $III$ is correct.

To convert $1$-butyne to $1-D$-butanal,one would carry out the following steps :
$(I)$ Sodium amide,then $D_2O$
$(II)$ Disiamylborane,then hydrogen peroxide/sodium hydroxide
$(III)$ The transformation can not be carried out with the indicated reagents.

Similar Questions

What is the increasing order of acidity for the following substances?
$(1)$ $CH_2=CH_2$
$(2)$ $CH_3-CH_3$
$(3)$ $HC \equiv CH$
$(4)$ $NH_3$

$CH \equiv CH + CO + H_2O \xrightarrow{Ni(CO)_4} \text{Product}$. For this reaction,which statement is false?

The correct order for acid strength of compounds $CH \equiv CH$,$CH_3 - C \equiv CH$,and $CH_2 = CH_2$ is as follows:

Acetylene reacts with dilute $H_2SO_4$ in the presence of $HgSO_4$ to produce .......

When $1,2-$dibromopropane is treated with $X$ moles of $NaNH_2$,the resulting compound reacts with ethyl bromide to form pentyne. What is the value of $X$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

To convert $1$-butyne to $1-D$-butanal,one would carry out the following steps :$(I)$ Sodium amide,then $D_2O$$(II)$ Disiamylborane,then hydrogen peroxide/sodium hydroxide$(III)$ The transformation can not be carried out with the indicated reagents.