(C) According to Charles's Law,for a given mass of an ideal gas at constant pressure,the volume is directly proportional to the absolute temperature:

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(C) According to Charles's Law,for a given mass of an ideal gas at constant pressure,the volume is directly proportional to the absolute temperature: $V \propto T$.This implies: $\frac{V_1}{V_2} = \frac{T_1}{T_2}$.Given: $V_1 = V$,$V_2 = 2V$,and $T_1 = 27^{\circ}C = 27 + 273 = 300 \ K$.Substituting the values: $\frac{V}{2V} = \frac{300}{T_2}$.Solving for $T_2$: $T_2 = 300 \times 2 = 600 \ K$.Converting back to degrees Celsius: $T_2(^{\circ}C) = 600 - 273 = 327^{\circ}C$.

Class 11 Physics Kinetic Theory Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

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To double the volume of a given mass of an ideal gas at $27^{\circ}C$ keeping the pressure constant,one must raise the temperature in degrees Celsius to ....... $^{\circ}C$.

IIT 1975 All IIT

A
$54$
B
$270$
C
$327$
D
$600$

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Gas Laws (Charles, Boyle's, Avagadro's, Gay Lussacs and Dalton's law) and Ideal gas Equation

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Column-$I$	Column-$II$
$(a)$ Top graph	$(i)$ Constant pressure
$(b)$ Bottom graph	$(ii)$ Constant volume
	$(iii)$ For ideal gas

To double the volume of a given mass of an ideal gas at $27^{\circ}C$ keeping the pressure constant,one must raise the temperature in degrees Celsius to ....... $^{\circ}C$.

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Column-$I$ represents a graph and Column-$II$ represents a physical quantity or condition that is constant for that graph. Match them correctly:
Column-$I$ Column-$II$
$(a)$ Top graph $(i)$ Constant pressure
$(b)$ Bottom graph $(ii)$ Constant volume
$(iii)$ For ideal gas