To establish an instantaneous displacement current of $2\,A$ in the space between two parallel plates of a $1\,\mu F$ capacitor,the potential difference across the capacitor plates will have to be changed at the rate of:

$A$ parallel plate capacitor with a plate separation of $2 \, mm$ is connected to an electric circuit with a source voltage of $400 \, V$. If the plate area is $60 \, cm^2$,what is the value of the displacement current for a time interval of $10^{-6} \, s$?

$A$ parallel plate capacitor of area $A = 16 \ cm^2$ and separation between the plates $10 \ cm$ is charged by a $DC$ current. Consider a hypothetical plane surface of area $A_0 = 3.2 \ cm^2$ inside the capacitor and parallel to the plates. At an instant,the current through the circuit is $6 \ A$. At the same instant,the displacement current through $A_0$ is . . . . . . $mA$.

$A$ circular parallel plate capacitor of radius $R$ and spacing $d$ is being charged by a constant current $I_D$. Find the magnetic field between the plates at a distance $r$ from the axis,where $r > R$.

What are Maxwell's equations? Write these equations.

You are given a $2 \,\mu F$ parallel plate capacitor. How would you establish an instantaneous displacement current of $1 \, mA$ in the space between its plates?