To get an output Y=1 from the circuit shown,t | vedclass

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(C) The given circuit consists of an $OR$ gate followed by an $AND$ gate. The Boolean expression for the output $Y$ is given by $Y = (A + B) \cdot C$.

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$1, 0, 1$

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(C) The given circuit consists of an $OR$ gate followed by an $AND$ gate. The Boolean expression for the output $Y$ is given by $Y = (A + B) \cdot C$.For the output to be $Y = 1$,both inputs to the $AND$ gate must be $1$. Therefore,$(A + B) = 1$ and $C = 1$.Checking the options:For option $C$: $A = 1, B = 0, C = 1$.Substituting these values: $Y = (1 + 0) \cdot 1 = 1 \cdot 1 = 1$.Thus,the inputs $A = 1, B = 0, C = 1$ result in an output $Y = 1$.

To get an output $Y=1$ from the circuit shown,the inputs $A, B,$ and $C$ must be respectively:

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