To get the truth table shown from the followi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given circuit consists of an $OR$ gate with two inputs. One input is $A$ and the other input is the output of gate $G$, which takes $A$ and $B

Vedclass · Accepted Answer

$AND$ gate.

Vedclass · Answer

(C) The given circuit consists of an $OR$ gate with two inputs. One input is $A$ and the other input is the output of gate $G$, which takes $A$ and $B$ as inputs. Let the output of gate $G$ be $X$. Then the final output $Y = A + X$.From the truth table:For $A=0, B=0$, $Y=0$. Since $Y = A + X$, $0 = 0 + X \implies X=0$.For $A=0, B=1$, $Y=0$. Since $Y = A + X$, $0 = 0 + X \implies X=0$.For $A=1, B=0$, $Y=1$. Since $Y = A + X$, $1 = 1 + X \implies X$ can be $0$ or $1$.For $A=1, B=1$, $Y=1$. Since $Y = A + X$, $1 = 1 + X \implies X$ can be $0$ or $1$.Looking at the values of $X$ derived from the inputs $A$ and $B$: when $A=0, B=0 \implies X=0$; when $A=0, B=1 \implies X=0$; when $A=1, B=0 \implies X=0$ (consistent with $Y=1$); when $A=1, B=1 \implies X=1$ (consistent with $Y=1$).This truth table for $X$ (inputs $A, B$ and output $X$) corresponds to the $AND$ gate, where $X = A \cdot B$.

To get the truth table shown from the following logic circuit, the gate $G$ should be

Similar Questions

For the logic circuit shown in the figure,the Boolean expression is:

The figure shows two $NAND$ gates followed by a $NOR$ gate. The system is equivalent to the following logic gate:

Which of the following gates will have an output of $1$?

Which of the following is the correct truth table for the logic gate circuit shown in the figure?

The Boolean equation of a $NOR$ gate is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module