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(A) The resolving power of a telescope is given by $R = \frac{a}{1.22 \lambda}$,where $a$ is the diameter (aperture) of the objective lens and $\lambd

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Both the focal length and aperture of the objective have to be increased

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(A) The resolving power of a telescope is given by $R = \frac{a}{1.22 \lambda}$,where $a$ is the diameter (aperture) of the objective lens and $\lambda$ is the wavelength of light.To increase the resolving power,we must increase the aperture $a$.The magnifying power of a telescope is given by $m = \frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective and $f_e$ is the focal length of the eyepiece.To increase the magnifying power,we must increase the focal length of the objective $f_o$.Therefore,to increase both the resolving power and the magnifying power,both the aperture and the focal length of the objective lens must be increased.

To increase both the resolving power and magnifying power of a telescope:

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Assertion: The resolving power of a telescope is more if the diameter of the objective lens is more.
Reason: Objective lens of large diameter collects more light.

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