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(D) At maximum compression,the kinetic energy of the car is converted entirely into the potential energy of the spring.First,convert the speed from $k

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$2$

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(D) At maximum compression,the kinetic energy of the car is converted entirely into the potential energy of the spring.First,convert the speed from $km/h$ to $m/s$:$v = 18.0 \; km/h = 18.0 	imes \frac{5}{18} \; m/s = 5 \; m/s$.The kinetic energy $K$ of the moving car is:$K = \frac{1}{2} m v^2 = \frac{1}{2} 	imes 1000 \; kg 	imes (5 \; m/s)^2 = 500 	imes 25 = 1.25 	imes 10^4 \; J$.According to the law of conservation of mechanical energy,at maximum compression $x_m$,the potential energy $V$ of the spring equals the kinetic energy $K$ of the car:$V = \frac{1}{2} k x_m^2 = K$.Substituting the values:$\frac{1}{2} 	imes (6.25 	imes 10^3) 	imes x_m^2 = 1.25 	imes 10^4$.$x_m^2 = \frac{2 	imes 1.25 	imes 10^4}{6.25 	imes 10^3} = \frac{2.5 	imes 10^4}{6.25 	imes 10^3} = 0.4 	imes 10 = 4$.$x_m = \sqrt{4} = 2 \; m$.

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