To synthesize the unsymmetrical alkyne CH_3-C | vedclass

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(D) The synthesis of the unsymmetrical alkyne $CH_3-C\equiv C-CH_2-CH_3$ involves the stepwise alkylation of ethyne $(CH\equiv CH)$.Step $1$: Ethyne r

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Ethyne,iodomethane,iodoethane and sodamide

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(D) The synthesis of the unsymmetrical alkyne $CH_3-C\equiv C-CH_2-CH_3$ involves the stepwise alkylation of ethyne $(CH\equiv CH)$.Step $1$: Ethyne reacts with sodamide $(NaNH_2)$ to form sodium acetylide $(CH\equiv C^{-}Na^{+})$.Step $2$: Sodium acetylide reacts with iodomethane $(CH_3I)$ to form propyne $(CH\equiv C-CH_3)$.Step $3$: Propyne is treated with another equivalent of $NaNH_2$ to form the sodium salt of propyne $(CH_3-C\equiv C^{-}Na^{+})$.Step $4$: This salt reacts with iodoethane $(C_2H_5I)$ via an $S_N2$ reaction to yield the final product $CH_3-C\equiv C-CH_2-CH_3$.

To synthesize the unsymmetrical alkyne $CH_3-C\equiv C-CH_2-CH_3$,the reagents needed would be:

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