Toluene on oxidation with dilute HNO_3 and al | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The oxidation of alkyl benzenes (like toluene) with strong oxidizing agents such as alkaline $KMnO_4$ results in the oxidation of the alkyl side c

Vedclass · Accepted Answer

Benzoic acid

Vedclass · Answer

(D) The oxidation of alkyl benzenes (like toluene) with strong oxidizing agents such as alkaline $KMnO_4$ results in the oxidation of the alkyl side chain to a carboxylic acid group. Even in the presence of dilute $HNO_3$,the strong oxidizing action of alkaline $KMnO_4$ converts the methyl group $(-CH_3)$ of toluene into a carboxyl group $(-COOH)$. Thus,toluene is oxidized to benzoic acid $(C_6H_5COOH)$.

Toluene on oxidation with dilute $HNO_3$ and alkaline $KMnO_4$ gives:

Similar Questions

Discuss the formation of cancer-causing polynuclear hydrocarbons and explain how they cause cancer.

What is the role of $HNO_3$ in the nitrating mixture used for the nitration of benzene?

The following reaction is given:
$\xrightarrow{\text{Electrolysis}} A$
$A$ is

Which of the following compounds is/are not aromatic?

What is the expected order of reactivity of the following compounds in electrophilic chlorination $(Cl_2 + FeCl_3)$? (more reactive $ > $ less reactive)
$I: C_6H_5CH_2CO_2H$
$II: C_6H_5N(CH_3)_2$
$III: C_6H_5OCOCH_3$
$IV: C_6H_5CCl_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module