(B) $1$. Toluene $(C_6H_5CH_3)$ reacts with excess $Cl_2$ in the presence of sunlight (free radical substitution) to form benzotrichloride $(C_6H_5CCl

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(B) $1$. Toluene $(C_6H_5CH_3)$ reacts with excess $Cl_2$ in the presence of sunlight (free radical substitution) to form benzotrichloride $(C_6H_5CCl_3)$.$2$. Benzotrichloride on hydrolysis gives benzoic acid $(C_6H_5COOH)$.$3$. Benzoic acid reacts with $NaOH$ (an acid-base reaction) to form sodium benzoate $(C_6H_5COONa)$.Therefore,the final product is sodium benzoate.

Class 12 Chemistry Haloalkanes and Haloarenes Properties of Haloalkanes

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Toluene reacts with excess of $Cl_2$ in the presence of sunlight to give a product which on hydrolysis followed by reaction with $NaOH$ gives:

A
Benzoic acid
B
Sodium benzoate
C
Sodium phenoxide
D
None of these

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Haloalkanes and Haloarenes

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Properties of Haloalkanes

Benzene $\xrightarrow[{Anhy. AlCl_3}]{{CH_3Cl}} A \,$ $\xrightarrow[{hv}]{{Cl_2 (1 \, mole)}} B$ $\xrightarrow{{AgCN}} C$
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MediumJEE MAIN 2023

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$A$ solution of $D(+)-1-$chloro$-1-$phenylethane in toluene racemises slowly in the presence of a small amount of $SbCl_5$,due to the formation of:

DifficultIIT 1999

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Toluene reacts with excess of $Cl_2$ in the presence of sunlight to give a product which on hydrolysis followed by reaction with $NaOH$ gives:

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Benzene $\xrightarrow[{Anhy. AlCl_3}]{{CH_3Cl}} A \,$ $\xrightarrow[{hv}]{{Cl_2 (1 \, mole)}} B$ $\xrightarrow{{AgCN}} C$
Which is correct for the above reaction?