(C) In the complex $[MnO_4]^-$,the oxidation state of $Mn$ is calculated as $x + 4(-2) = -1$,which gives $x = +7$. The electronic configuration of $Mn

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(C) In the complex $[MnO_4]^-$,the oxidation state of $Mn$ is calculated as $x + 4(-2) = -1$,which gives $x = +7$. The electronic configuration of $Mn$ $(Z=25)$ is $[Ar] 3d^5 4s^2$. For $Mn^{7+}$,the configuration is $[Ar] 3d^0$. Since there are no electrons in the $d$-orbitals,the number of electrons in the $e_g$ orbitals is $0$.