Total number of d electrons present in an ele | vedclass

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(D) The atomic number of Platinum $(Pt)$ is $78$. The electronic configuration of $Pt$ is $[Xe] 4f^{14} 5d^9 6s^1$. To find the total number of $d$ el

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$29$

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(D) The atomic number of Platinum $(Pt)$ is $78$. The electronic configuration of $Pt$ is $[Xe] 4f^{14} 5d^9 6s^1$. To find the total number of $d$ electrons,we look at the inner shells as well: $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^{10} 5s^2 5p^6 4f^{14} 5d^9 6s^1$. Total $d$ electrons = $3d^{10} + 4d^{10} + 5d^9 = 10 + 10 + 9 = 29$.

Total number of $d$ electrons present in an element with atomic number $78$ is:

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