Transition elements show high melting points. Why?
(N/A) In transition elements,the $(n-1)d$-electrons are involved in interatomic metallic bonding in addition to $ns$ electrons. This increased number of electrons participating in metallic bonding leads to stronger metallic bonds,which results in high melting points.
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Similar Questions
Match the following:
List-$I$ (Element) List-$II$ (Block) $A$. $Cd$ $I$. $f$-block $B$. $Eu$ $II$. $s$-block $C$. $Se$ $III$. $d$-block $D$. $Ba$ $IV$. $p$-block
The correct answer is:
| List-$I$ (Element) | List-$II$ (Block) |
| $A$. $Cd$ | $I$. $f$-block |
| $B$. $Eu$ | $II$. $s$-block |
| $C$. $Se$ | $III$. $d$-block |
| $D$. $Ba$ | $IV$. $p$-block |
The correct answer is:
Match List-$I$ with List-$II$:
List-$I$ ($\text{Transition metal ion}$) List-$II$ ($\text{Spin only magnetic moment (B.M.)}$) $A$. $Ti^{3+}$ $I$. $3.87$ $B$. $V^{2+}$ $II$. $0.00$ $C$. $Ni^{2+}$ $III$. $1.73$ $D$. $Sc^{3+}$ $IV$. $2.84$
Choose the correct answer from the options given below:
| List-$I$ ($\text{Transition metal ion}$) | List-$II$ ($\text{Spin only magnetic moment (B.M.)}$) |
|---|---|
| $A$. $Ti^{3+}$ | $I$. $3.87$ |
| $B$. $V^{2+}$ | $II$. $0.00$ |
| $C$. $Ni^{2+}$ | $III$. $1.73$ |
| $D$. $Sc^{3+}$ | $IV$. $2.84$ |
Choose the correct answer from the options given below:
Which of the following will be a coloured ion?
Easy
View SolutionThe correct order of atomic/ionic radii is
Difficult
View SolutionThe most abundant transition metal in the earth's crust is
Easy
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