The transition state of the given S_N2 reacti | vedclass

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(D) In an $S_N2$ reaction,the nucleophile $(RO^-)$ attacks the electrophilic carbon from the side opposite to the leaving group $(Br^-)$. This results

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(D) In an $S_N2$ reaction,the nucleophile $(RO^-)$ attacks the electrophilic carbon from the side opposite to the leaving group $(Br^-)$. This results in a pentacoordinate transition state where the carbon atom is partially bonded to both the incoming nucleophile and the leaving group. Both the nucleophile and the leaving group carry a partial negative charge $(\delta^-)$ in the transition state. Looking at the options,option $D$ correctly represents this transition state with the nucleophile $OR$ and the leaving group $Br$ having partial negative charges $(\delta^-)$ and the carbon atom in a trigonal bipyramidal arrangement.

The transition state of the given $S_N2$ reaction is:

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