Two $10 \; cm$ long,straight wires,each carrying a current of $5 \; A$,are kept parallel to each other. If each wire experiences a force of $10^{-5} \; N$,then the separation between the wires is $\dots \; cm$.

The net charge in a current-carrying wire is zero,yet a magnetic field exerts a force on it. This is because a magnetic field exerts a force on:

$A$ straight horizontal conducting rod of length $L$ and mass $M$ is suspended by two vertical wires at its ends. If $I$ is the current passing through the rod,then in order that the tension in the wires is zero,the magnetic field set up normal to the conductor is (Neglect the mass of the wire,$g$ = acceleration due to gravity).

Three parallel wires $a$, $b$, and $c$ carrying currents $i_a$, $i_b$, and $i_c$ as shown in the figure are placed next to each other. The magnitude of the force on a length $l$ of the wire $a$, if $d_2 = 2 d_1$, $i_b = i_a$, and $i_c = 4 i_a$ is:

Two long and parallel wires are at a distance of $0.1\, m$ and a current of $5\, A$ is flowing in each of these wires. The force per unit length due to these wires will be

$A$ rectangular loop carrying a current $i$ is situated near a long straight wire such that the wire is parallel to one of the sides of the loop and is in the plane of the loop. If a steady current $i$ is established in the wire as shown in the figure,the loop will