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(B) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.The event is defined as the sum of the

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$\frac{1}{18}$

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(B) When two balanced dice are rolled simultaneously,the total number of possible outcomes is $6 	imes 6 = 36$.The event is defined as the sum of the numbers on the two dice being $11$.The possible outcomes that result in a sum of $11$ are $(5, 6)$ and $(6, 5)$.Thus,the number of favorable outcomes is $m = 2$.The probability $P$ of the event is given by the ratio of favorable outcomes to total outcomes:$P = \frac{m}{n} = \frac{2}{36} = \frac{1}{18}$.

Two balanced dice are rolled simultaneously. Then,the probability that the sum of numbers on the dice is $11$ is .........

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