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(B) When two balanced dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event that the sum of the numbers on t

Vedclass · Accepted Answer

$\frac{5}{36}$

Vedclass · Answer

(B) When two balanced dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event that the sum of the numbers on the two dice is $8$.The possible outcomes for the sum to be $8$ are: $(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)$.The number of favorable outcomes is $5$.Therefore,the probability $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of possible outcomes}} = \frac{5}{36}$.

Two balanced dice are rolled simultaneously. Then,the probability that the sum of numbers on the dice is $8$ is ........

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