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(C) Let the height of the tower be $h$. According to the law of conservation of mechanical energy, the total energy at the top of the tower is equal t

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Both the balls reach the ground with the same velocity.

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(C) Let the height of the tower be $h$. According to the law of conservation of mechanical energy, the total energy at the top of the tower is equal to the total energy at the ground level.For ball $A$ (thrown upwards): Initial energy $E_A = \frac{1}{2}mu^2 + mgh$. Final energy at ground $E'_A = \frac{1}{2}mv_A^2 + 0$.By conservation of energy: $\frac{1}{2}mu^2 + mgh = \frac{1}{2}mv_A^2$, which gives $v_A = \sqrt{u^2 + 2gh}$.For ball $B$ (thrown downwards): Initial energy $E_B = \frac{1}{2}mu^2 + mgh$. Final energy at ground $E'_B = \frac{1}{2}mv_B^2 + 0$.By conservation of energy: $\frac{1}{2}mu^2 + mgh = \frac{1}{2}mv_B^2$, which gives $v_B = \sqrt{u^2 + 2gh}$.Since both balls start with the same initial speed $u$ from the same height $h$, they will both reach the ground with the same final velocity $v = \sqrt{u^2 + 2gh}$.Therefore, option $C$ is the correct answer.

Two balls $A$ and $B$ are thrown with the same velocity $u$ from the top of a tower. Ball $A$ is thrown vertically upwards and ball $B$ is thrown vertically downwards. Choose the correct statement.

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