(B) The de Broglie wavelength is given by $\lambda = \frac{h}{mv}$.Given: $m_1 = 100 \ g$, $m_2 = 50 \ g$, and $v_2 = 1.5 \ v_1$.The ratio of waveleng

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(B) The de Broglie wavelength is given by $\lambda = \frac{h}{mv}$.Given: $m_1 = 100 \ g$, $m_2 = 50 \ g$, and $v_2 = 1.5 \ v_1$.The ratio of wavelengths is $\frac{\lambda_1}{\lambda_2} = \frac{h / (m_1 v_1)}{h / (m_2 v_2)} = \frac{m_2 v_2}{m_1 v_1}$.Substituting the values: $\frac{\lambda_1}{\lambda_2} = \frac{50 \times 1.5 \ v_1}{100 \times v_1} = \frac{75}{100} = \frac{3}{4}$.Thus, the ratio is $3 : 4$.

Class 11 Chemistry Structure of Atom De Broglie's principle

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Two base balls (masses: $m_1 = 100 \ g$ and $m_2 = 50 \ g$) are thrown. Both of them move with uniform velocity, but the velocity of $m_2$ is $1.5$ times that of $m_1$. The ratio of de Broglie wavelengths $\lambda(m_1) : \lambda(m_2)$ is given by

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A
$4 : 3$
B
$3 : 4$
C
$2 : 1$
D
$1 : 2$

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Structure of Atom

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De Broglie's principle

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Two base balls (masses: $m_1 = 100 \ g$ and $m_2 = 50 \ g$) are thrown. Both of them move with uniform velocity, but the velocity of $m_2$ is $1.5$ times that of $m_1$. The ratio of de Broglie wavelengths $\lambda(m_1) : \lambda(m_2)$ is given by

Similar Questions

The de-Broglie wavelength $(\lambda)$ for electron $(e)$, proton $(p)$ and $He^{2+}$ ion $(\alpha)$ are in the following order. (Speed of $e$, $p$ and $\alpha$ are the same)

If the radius of the first orbit of $H$ atom is $a_0$, what is the de-Broglie wavelength of an electron in the third orbit (in $\pi a_0$)?

Calculate the velocity of an electron having a de Broglie wavelength of $58 \ nm$ and mass $9.1 \times 10^{-31} \ kg$. Given: $h = 6.63 \times 10^{-34} \ Js$.

The kinetic energy of an electron is $4.55 \times 10^{-25} \ J$. Find its wavelength.

What is the de Broglie wavelength of an object with a mass of $0.1 \ kg$ moving with a velocity of $10 \ m/s$? What does this value indicate?

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