Two batteries of e.m.f 4 text{ V} and 8 text{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The circuit consists of two batteries connected in series opposition. The net e.m.f is $E_{net} = 8 	ext{ V} - 4 	ext{ V} = 4 	ext{ V}$.The tot

Vedclass · Accepted Answer

$\frac{1}{3} 	ext{ A}$ and $3 	ext{ V}$

Vedclass · Answer

(B) The circuit consists of two batteries connected in series opposition. The net e.m.f is $E_{net} = 8 	ext{ V} - 4 	ext{ V} = 4 	ext{ V}$.The total resistance of the circuit is $R_{total} = R + r_1 + r_2 = 9 \Omega + 1 \Omega + 2 \Omega = 12 \Omega$.The current in the circuit is $I = \frac{E_{net}}{R_{total}} = \frac{4 	ext{ V}}{12 \Omega} = \frac{1}{3} 	ext{ A}$.The potential difference between points $P$ and $Q$ is the voltage across the external resistor $R = 9 \Omega$.$V_{PQ} = I 	imes R = \frac{1}{3} 	ext{ A} 	imes 9 \Omega = 3 	ext{ V}$.

Two batteries of e.m.f $4 \text{ V}$ and $8 \text{ V}$ with internal resistance $1 \Omega$ and $2 \Omega$ respectively are connected in a circuit with a resistance of $9 \Omega$ as shown in the figure. The current and potential difference between the points $P$ and $Q$ is

Similar Questions

The total current supplied to the following circuit by the battery is (in $ A$)

The diagram shows a circuit. Choose the incorrect statement.

In the given circuit, the cells have zero internal resistance. The currents (in Amperes) passing through resistance $R_1$ and $R_2$ respectively, are

Two resistors whose values are in the ratio $2 : 1$ are connected in parallel with one cell. The ratio of power dissipated is:

In the circuit diagram shown below,the magnitude and direction of the flow of current respectively would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module