(A) For body $A$ starting from rest (initial velocity $u=0$): $S_A = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2}at^2 = \frac{1}{2}at^2$ For body $B$ moving

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(A) For body $A$ starting from rest (initial velocity $u=0$): $S_A = ut + \frac{1}{2}at^2 = 0 + \frac{1}{2}at^2 = \frac{1}{2}at^2$ For body $B$ moving with uniform velocity $V$: $S_B = Vt$ Since they meet at the same point after time $t$,their displacements must be equal: $S_A = S_B$ $\frac{1}{2}at^2 = Vt$ Dividing both sides by $t$ (assuming $t \neq 0$): $\frac{1}{2}at = V$ $t = \frac{2V}{a}$

Class 11 Physics Motion in a Straight Line Uniformly Accelerated Motion

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Two bodies $A$ and $B$ start from the same point at the same instant and move along a straight line. Body $A$ moves with uniform acceleration $a$ and body $B$ moves with uniform velocity $V$. They meet after time $t$. The value of $t$ is

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A
$\frac{2V}{a}$
B
$\frac{a}{2V}$
C
$\frac{V}{2a}$
D
$\sqrt{\frac{V}{a}}$

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Motion in a Straight Line

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Uniformly Accelerated Motion

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$A$ particle located at $x= 0$ at time $t= 0$ starts moving along the positive $x-$direction with a velocity $v$ that varies as $v = \alpha \sqrt{x}$. The displacement of the particle varies with time as:

MediumAIEEE 2006

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The motion of a body is given by the equation $\frac{dv(t)}{dt} = 6.0 - 3v(t)$,where $v(t)$ is speed in $m/s$ and $t$ is in $s$. If the body was at rest at $t = 0$,which of the following statements is correct?

DifficultIIT 1995

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Two bodies $A$ and $B$ start from the same point at the same instant and move along a straight line. Body $A$ moves with uniform acceleration $a$ and body $B$ moves with uniform velocity $V$. They meet after time $t$. The value of $t$ is

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