Two bodies of masses 2,kg and 4,kg are moving | vedclass

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(C) The velocity of the centre of mass of a system is given by $v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}$.Since the bodies are moving towards each o

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(C) The velocity of the centre of mass of a system is given by $v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}$.Since the bodies are moving towards each other due to mutual gravitational attraction,there is no external force acting on the system $(F_{ext} = 0)$.According to the law of conservation of momentum,if the initial velocity of the system is zero,the velocity of the centre of mass remains zero throughout the motion.Given that the bodies were at rest initially,the initial momentum of the system is $P_i = m_1(0) + m_2(0) = 0$.Therefore,the velocity of the centre of mass $v_{cm} = 0\,m/s$.

Two bodies of masses $2\,kg$ and $4\,kg$ are moving with velocities $2\,m/s$ and $10\,m/s$ respectively towards each other due to mutual gravitational attraction. What is the velocity of their centre of mass,given that the bodies were at rest initially?

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