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(C) The kinetic energy $K$ of a body of mass $m$ and momentum $P$ is given by the relation $K = \frac{P^2}{2m}$.Since both bodies have the same kineti

Vedclass · Accepted Answer

$\sqrt{\frac{m_1}{m_2}}$

Vedclass · Answer

(C) The kinetic energy $K$ of a body of mass $m$ and momentum $P$ is given by the relation $K = \frac{P^2}{2m}$.Since both bodies have the same kinetic energy,we can write:$K_1 = K_2$$\frac{P_1^2}{2m_1} = \frac{P_2^2}{2m_2}$Rearranging the terms to find the ratio of momenta $\frac{P_1}{P_2}$:$\frac{P_1^2}{P_2^2} = \frac{m_1}{m_2}$Taking the square root on both sides:$\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$Therefore,the correct option is $C$.

Two bodies of masses $m_1$ and $m_2$ are moving with the same kinetic energy. If $P_1$ and $P_2$ are their respective momenta,the ratio $\frac{P_1}{P_2}$ is equal to:

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