Two bodies with masses M_1 and M_2 have equal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The kinetic energy $K$ of a body of mass $m$ and momentum $p$ is given by the relation $K = \frac{p^2}{2m}$.Since the kinetic energies of the two

Vedclass · Accepted Answer

$\sqrt{M_1} : \sqrt{M_2}$

Vedclass · Answer

(D) The kinetic energy $K$ of a body of mass $m$ and momentum $p$ is given by the relation $K = \frac{p^2}{2m}$.Since the kinetic energies of the two bodies are equal,we have $K_1 = K_2$.Therefore,$\frac{p_1^2}{2M_1} = \frac{p_2^2}{2M_2}$.Rearranging the terms,we get $\frac{p_1^2}{p_2^2} = \frac{M_1}{M_2}$.Taking the square root on both sides,we obtain $\frac{p_1}{p_2} = \sqrt{\frac{M_1}{M_2}} = \sqrt{M_1} : \sqrt{M_2}$.

Two bodies with masses $M_1$ and $M_2$ have equal kinetic energies. If $p_1$ and $p_2$ are their respective momenta,then $p_1/p_2$ is equal to

Similar Questions

If a light object (mass $M_1$ and velocity $V_1$) and a heavy object (mass $M_2$ and velocity $V_2$) have the same kinetic energy,then which of the following is true regarding their momenta ($P_1 = M_1 V_1$ and $P_2 = M_2 V_2$)?

When the speed of a vehicle increases by $2 \ m/s$,its kinetic energy doubles. What is the original speed of the vehicle?

The kinetic energy possessed by a body of mass $m$ moving with a velocity $v$ is equal to $\frac{1}{2}mv^2$,provided

The kinetic energy of a body is increased by $4$ times. Its momentum will

Two bodies of masses $m$ and $4m$ are moving with equal kinetic energy $(K.E.)$. The ratio of their linear momentums is

Vedclass Test Series

Exam Paper Generator

Online Exam Module