Two capacitances of capacity $C_1$ and $C_2$ are connected in series and a potential difference $V$ is applied across the combination. The potential difference across $C_1$ will be:

Two capacitors of capacities $2 \mu F$ and $4 \mu F$ are connected in parallel. $A$ third capacitor of $6 \mu F$ capacity is connected in series with this combination. $A$ battery of $12 \text{ V}$ is connected across this combination. The charge on the $2 \mu F$ capacitor is: (in $\mu C$)

Four capacitors are connected as shown in the adjoining figure. The capacitance of each is $8\,\mu F$. The equivalent capacitance between the points $A$ and $B$ will be......$\mu F$.

Five capacitors,each of capacity $C$,are connected as shown in the figure. The resultant capacity between $A$ and $B$ is $14 \mu F$. The capacity of each capacitor is (in $\mu F$)

Find the equivalent capacitance between $A$ and $B$ of the following arrangement:

If there are $n$ capacitors,each of capacitance $C$,connected in parallel to a $V$ volt source,then the energy stored is equal to