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(B) Let the capacity of each capacitor be $C$.When two capacitors are joined in series,the equivalent capacity $C_s$ is given by:$\frac{1}{C_s} = \fra

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$1: 4$

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(B) Let the capacity of each capacitor be $C$.When two capacitors are joined in series,the equivalent capacity $C_s$ is given by:$\frac{1}{C_s} = \frac{1}{C} + \frac{1}{C} = \frac{2}{C} \implies C_s = \frac{C}{2}$.When two capacitors are joined in parallel,the equivalent capacity $C_p$ is given by:$C_p = C + C = 2C$.The ratio of the resultant capacity in series to that in parallel is:$\frac{C_s}{C_p} = \frac{C/2}{2C} = \frac{1}{4}$.Thus,the ratio is $1: 4$.

Two capacitors of same capacity are first joined in series and then in parallel. The ratio of resultant capacity in series to that in parallel combination will be

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