Two capillaries made of the same material have radii $r_1 = 1 \, mm$ and $r_2 = 2 \, mm$. If the rise of the liquid in the first capillary $(r_1 = 1 \, mm)$ is $30 \, cm$,then the rise in the other capillary will be ........ $cm$.

If the rise in heights of capillary of two tubes are $6.6\,cm$ and $2.2\,cm$,then the ratio of the radii of the tubes is

$A$ narrow glass capillary tube of radius $1.00 \ mm$ is dipped in a trough containing mercury. The amount by which the level of mercury dips down relative to the normal level outside the tube will be approximately $..... \ mm$.
$[$Surface tension of mercury at room temperature $= 0.465 \ N/m$,density of mercury $= 13.6 \times 10^3 \ kg/m^3$,angle of contact with glass $= 135^{\circ}$,$g = 9.8 \ m/s^2]$

Water rises to a height of $10 \ cm$ in a certain capillary tube. Another identical tube when dipped in mercury,the level of mercury is depressed by $3.42 \ cm$. The density of mercury is $13.6 \ g/cc$. The angle of contact for water in contact with glass is $0^o$ and for mercury in contact with glass is $135^o$. The ratio of the surface tension of water to that of $Hg$ is:

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary tube of radius $\frac{r}{3}$ will be:

Three liquids have the same surface tension and densities $\rho_1, \rho_2$ and $\rho_3$ $(\rho_1 < \rho_2 < \rho_3)$. In three identical capillaries, the rise of liquid is the same. The corresponding angles of contact $\theta_1, \theta_2$ and $\theta_3$ are related as: